Question

Suppose that f(π/6)=−4 and f′(π/6)=5, and let g(x)=f(x)sinx and h(x)=cosx/f(x). Answer the following questions.

Answer 1

@Callisto @Hero

Answer 2

find g'(pi/6) and h'(pi/6)

Answer 3

@ash2326

Answer 4

g'(x)=?

Answer 5

yeah the derivative of g(x)

Answer 6

and g(x) = f(x)* sin (x) . SO???? g'(x) = ?? product rule

Answer 7

Do you just want an example for g(x) and try by yourself h(x) or what?

Answer 8

g'(x)=f(x)cos(x)+sinxf'(x)?

Answer 9

doesnt matter to me @pitamar

Answer 10

*ok, go on, you know f(pi/6) and f'(pi/6) don't you? and you can find cos(pi/6) and sin(pi/6) pretty easily

Answer 11

yeah so its g'(pi/6)=((-4sqrt3)/2)+(5/2)

Answer 12

ok. ugly looking that way, but seems fine. so is it good enoug hof what? you could simplify it abit..

Answer 13

yeah it simplifies up to (5/2)-2sqrt3

Answer 14

ok if that's good enough you could go for h'(pi/6)

Answer 15

but i get stuck on h'(pi/6)

Answer 16

i dont really know the quotient rule

Answer 17

I see. so you should have said so hehe
Well, do you want a full explanation or just the the formula?

Answer 18

the formula

Answer 19

http://www.math.hmc.edu/calculus/tutorials/quotient_rule/
Here =]

Answer 20

There is a proof there too so that's good =]

Answer 21

thanks