Question

Find a function

Answer 1

(x-3)^2 and something.

Answer 2

y = a(x-h)^2 + k [vertex form for a parabola]

(h,k) [vertex of parabola]
(x,y) [ point on parabola]
a [ scalar value which needs to be solved for]

make sense or would you want more help?

Answer 3

This makes great sense friend! I need help putting it all together!

Answer 4

great
so what is needed next is for you to figure out what all these values are from the information given to you in the question:

x=?
y =?
h =?
k =?

can you do that from what I told you in the other response?

Answer 5

Thanks man, I think I got it.

Answer 6

you are welcome,
let me know if or when you get stuck!

Answer 7

I is stuck, can you tell me why 16(x-3)^2 +7 is not right? @DemolisionWolf

Answer 8

it looks like the a value of 16 is wrong,
so we have:
y = a(x-h)^2 + k
which becomes:
9 = a*(2-3)^2 + 7
then solve for a

Answer 9

9=a*1+7
9=A+7
2=A

Answer 10

yep you have it
so that answer is to take the vertex form, and plug in h, k, and a, while leaving x and y as x and y

Answer 11

Can you type that out for me?

Answer 12

@DemolisionWolf

Answer 13

haha, i can get you started, but i'm not allowed to post the answer!

recall:
y = a(x-h)^2 + k [vertex form for a parabola]
and you now know
a = 2,
h = 3,
k = 7,
so plug them in into the equation, i'll do the first:
y = a(x-h)^2 + k becomes
y = 2(x-h)^2 + k

now you finish putting in h and k

Answer 14

So 2(2-3)^2 -9?

Answer 15

@DemolisionWolf thanks

Answer 16

I mean +7

Answer 17

yes, almost!
2(2-3)^2 -9? has all the right numbers, you just need to do 2 things
do the "y=
y = 2(2-3)^2 -9
and don't plug in the number for x so get rid of the 2, and replace it with x

Answer 18

oh and replace the -9 with +7

Answer 19

I want my mommy

Answer 20

@DemolisionWolf

Answer 21

haha, then this is not your fault, this problem is on me, i missed something! one second!

Answer 22

And it passes through (2, -9)

Answer 23

So why +7?

Answer 24

gosh, i see what I did wrong, you've done nothing wrong it was me!
remember when you got a=16,
you were mostly right and I was wrong a dose't equal 2
a = -16