Question

You have challenged four other students to come up with expressions equal to x3. Their submissions are below.

Answer 1

where below ?

Answer 2

Working on it hold tight please - thanks!!!

Answer 3

Blake

Answer 4

do you know how to multiply these things?

Answer 5

@RED123url no i dont I can't find it in my lesson. I am struggling with division... there are four pics/student answers total so sit tight thanks

Answer 6

\[\Large x ^{m} \times x ^{n} = x ^{m+n}\]

Answer 7

Zoe

Answer 8

\[\Large \frac{ x ^{m} }{ x ^{n}} = x ^{m-n}\]

Answer 9

Eloise

Answer 10

Dylan

Answer 11

Okay thank you for your patience. Now, can I please get some kind of explaination on how to solve these problems? I'm so stuck. I'm not asking that you do my work for me, just help please.
@ranga @RED123url

Answer 12

I guess the guy did everything just follow the formulas he provided

Answer 13

I will do the first one:
\[\Large x ^{\frac{ 4 }{ 3 }} \times x ^{\frac{ 7 }{3 }} = x ^{\frac{ 4 }{ 3 } + \frac{ 7 }{ 3 }} = x ^{\frac{ 11 }{ 3 }}\]
\[\Large \frac{ x ^{\frac{ 11 }{ 3 }} }{ x ^{\frac{ 2 }{ 3}} } = x ^{\frac{ 11 }{ 3 } - \frac{ 2 }{ 3 }} = x ^{\frac{ 9 }{ 3 }} = x ^{3}\]

Answer 14

What kind of a weird challenge is that?

Anyway, also helpful to remember is that \(\sqrt[n]{x} = x^\frac{1}{n}\)

Answer 15

@ranga Thank you. So, what you are showing in your response is that the first problem set up checks out and is correct to what the question is asking?

And do you think you could just explain what the third and fourth ones are saying and how to go about them? That would REALLY help.

Answer 16

@sacapuntas - thank you!!!

Answer 17

Yes the first one is properly set up and is correct. For the 3rd and 4th one use the formula that sacapuntas provided along with the two formulae I provided earlier.

I will do the third one but this equation editor takes a long time.

Answer 18

\[\Large x ^{\frac{ 1 }{ 3 }}\times x ^{\frac{ 2 }{ 3}}\times x ^{\frac{ 4 }{ 3 }} \times \sqrt[3]{x} = x ^{\frac{ 1 }{ 3 }+\frac{ 2 }{ 3 }+\frac{ 4 }{ 3 }}\times x ^{\frac{ 1 }{ 3 }}\]
\[\Large = x ^{\frac{ 7 }{3 }} \times x ^{\frac{ 1 }{ 3 }} = x ^{\frac{ 7+1 }{ 3 }} = x ^{\frac{ 8 }{ 3 }}\]

Answer 19

That was the fourth one not third.

Answer 20

Thank you so much you are a life saver! @ranga

Answer 21

You are welcome.