For the reaction, calculate how many moles of the product form when 0.016mol of O2 completely reacts.
Assume that there is more than enough of the other reactant.
2Ca(s)+O2(g)→2CaO(s)

Question

For the reaction, calculate how many moles of the product form when 0.016mol of O2 completely reacts. 
Assume that there is more than enough of the other reactant.
2Ca(s)+O2(g)→2CaO(s)

wolfe8 · Answer

First, can you see if it is balanced?

toxicsugar22 · Answer

yes it is balance

wolfe8 · Answer

So here is how I interpret your equation. 2 parts of Ca with 1 part of O2 gives 2 parts of CaO. So if you know the amount of any substance, you can find it for the rest. Can you get the number of moles of whatever substance you have?

toxicsugar22 · Answer

ca mole is 40.078

toxicsugar22 · Answer

o2 mole is 32

toxicsugar22 · Answer

and 2cao mole is 56.078

toxicsugar22 · Answer

canyou just provide me with solutions and answeer to this please

wolfe8 · Answer

What you calculated are the RAM/RMMs. You divide the mass of a substance with its RMM to get the moles. I will link something here that should help you.

wolfe8 · Answer

http://openstudy.com/study#/updates/5260ae13e4b0c23cd54a5230

toxicsugar22 · Answer

can you help me solve the anser to it

toxicsugar22 · Answer

please

primeralph · Answer

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