series question
how do i start?
Plug in 1 for n, for next term plug in 2 for n And so forth. Good?
\[a_n = (3-1(2^{-1}) + (3-2(2^{-2}) +...+ (3-n(2^{-n})\] thats all?
Nothing more, and then find the sum of the series.
I mean you put in pluses already, but there is an easier way to find the sum of the series. Write out the series and I'll show, OK?
is it a geometric series?
Write it out, and will see.
(2.5 +2.5 +2.625 + ...)
Can you please put it in fractions?
( 5/2 + 5/2 + 21/8 +...)
The series is infinite, so if the terms are increasing you can't find the sum
Are they?
i have no idea
OK, looking at the series, your exponents are becoming negative and therefore the bigger the n the bigger the fraction is going to be formed, Now look at the problem closely keeping what I told you in mind. Would you agree that the bigger it is going to get the more it is going to approach 3? (they are not asking for exact sum, b/c it doesn't exist in infinite series.
@mathsnerd101, do you see why is the series ('s sum) going to approach 3 the bigger the series gets?
So the answer is 3.
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