Question

MAX h(x) = f(x) - g(x)

f(x) = 29x – x^2

g(x) = x^2 + x + 10

Answer 1

First find h(x),
\[h(x)=29x-x^2-(x^2+x+10)\]Simplify. Then find the derivative, h'(x) and do,
\[h'(x)=0\]Solve for x, and study the sign of h'(x).

Answer 2

Iam getting h(x)=-2x^2+28x-10
h´(x)=-4x+28
h'(x) =
how do you get the (-6x)

Answer 3

Because I confused a 2 with a 3 in the power. You are correct!!
\[h(x)=−2x^2+28x−10\\
h'(x)=-4x+28
\\-4x+28=0\Rightarrow x=-7\]