Need help with an area question!

Question

dls · Answer

Using integration find the area of that part of circle x^2+y^2=16, which is exterior to the parabola y^2=6x

dls · Answer

I think this is it http://www.meritnation.com/img/shared/discuss_editlive/3781436/2013_01_08_01_28_47/zcfcillg9019123108422458984.jpg

dls · Answer

I want to know where am I wrong if i do it like this..
4pi is the area for1 quadrant.so
Required area,
$$\LARGE 4\pi + 4\pi + 2 \int\limits_0^\sqrt{12}\frac{y^2}{6}dy$$

dls · Answer

@ganeshie8 @hartnn

dls · Answer

xdy means bounded with y axis right?so..

ganeshie8 · Answer

your integral gives u area under parabola.
thats not the entire area

ganeshie8 · Answer

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anonymous · Answer

i would instead calculate the white area
and subtract it from the area of  the circle.
because you need to add one more integral for the area above the parabola

ganeshie8 · Answer

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