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Trigonometric Integrals \[\int\limits_{}^{}\cos ^{2}\theta \sin \theta \]
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put u = cos thetha
du = ...?
-sin t
du = -sin t dt so, -du = sin t dt
integral u^2 (-du) piece of cake :)
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I'm sorry I meant. \[\int\limits_{}^{}\cos ^{2}\theta \sin2\theta \] Is it still the same process Or is it different now
write sin 2t = 2 sint cost then put u= sin t
sorry, u= cos t
so iis it -1/2cos^4t
-2 integral u^3du -2/4 u^4 +c -1/2 (cos^4 t) +c yup, correct :)
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thanks so much for your help
welcome ^_^
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