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OpenStudy (nottim):

Write the chemical equation for the standard molar enthalpy of formation of potassium chlorate, KClO3

OpenStudy (nottim):

oh no you stopped typing

OpenStudy (anonymous):

143 J·mol−1·K−1 is the standard molar enthalpy but overall, this is as close as I can get :)

OpenStudy (anonymous):

oops. this is the enthalpy: −391 kJ·mol−1 that was the entropy

OpenStudy (nottim):

er...mind telling me how you figured it out, if im not asking to much....

OpenStudy (anonymous):

I used the information (equations) on this webiste: http://en.wikipedia.org/wiki/Standard_enthalpy_of_formation and plugged them in. sorry-- I'm horrible at explaining in my own words

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