How do I simplify this equation?!?! I have tried to several times, but I can't seem to ever get the correct answer. 4 + 2i / (2/3 + 1/2i) Help appreciated ASAP. Thank you. :)
guess i wud first get rid of fractions
multiply 6 top and bottom
May I ask why 6?
2/3 x 6 = 12/3 = 4 1/2 x 6 = 6/2 = 3 to get whole numbers
\(\huge \frac {4 + 2i}{\frac{2}{3} + \frac{1}{2}i}\)
^ is ur expression like above ?
yes that is the equation
shamil explained nicely why 6 did u get why 6 ? :)
yes i do now
\(\huge \frac {4 + 2i}{\frac{2}{3} + \frac{1}{2}i} \) \(\huge \frac {6 \times (4 + 2i)}{6 \times (\frac{2}{3} + \frac{1}{2}i)} \)
I now have 24 + 12i / 4 + 31 .
\[\frac{ 24 + 12i }{ 4 + 3i }\]
how will that further simplify? Would I find the conjugate of the denominator then multiply the top and bottom by it?
\(\huge \frac {4 + 2i}{\frac{2}{3} + \frac{1}{2}i} \) \(\huge \frac {6 \times (4 + 2i)}{6 \times (\frac{2}{3} + \frac{1}{2}i)} \) \(\huge \frac {24+12i}{4+3i} \)
exactly !
multiply top and bottom wid conjugate of denominator, so that u get the complex number in standard form
I got 132 - 24i / 25 , but that is not one of my choices. Did I do something wrong?
Could 132 - 24i / 25 become (132 / 25) - (24i / 25) ?
Yes.
You got the answer correct, but it can be written differently.
It's like 4 - 3 / 5 = 4/5 - 3/5
Thank you all so very much!! :)
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