Question

Help Please?????

Answer 1

\[x^{2}=-28\]

Answer 2

have you learnt imaginary numbers?

Answer 3

i was not present for notes the day this work was assigned.

Answer 4

ever seen this ?
\(\Large i=\sqrt{-1} \)

Answer 5

yes

Answer 6

good,
s take square root on both sides of
x^2=-28
what do u get ?

Answer 7

would i not square root x^2 = +-\[\sqrt{-28}\]

Answer 8

\(\Large x^2=-28 \implies x= \sqrt{-28}=\sqrt{-1}\sqrt{28}\)
got that ?

Answer 9

could i not \[x=\sqrt{-28 } \rightarrow = \sqrt{-4x7} = 2\sqrt{7}\] ??

Answer 10

@hartnn

Answer 11

oh and where did the negative sign go ?

Answer 12

im confused i hypothesized that.
or would it be \[-2\sqrt{7}\] ??

Answer 13

@hartnn

Answer 14

but did u not get what i did here ??
\(\Large x^2=-28 \implies x= \sqrt{-28}=\sqrt{-1}\sqrt{28}\)

here we see the sqrt -1 which is actually = i as i said before

Answer 15

so,
\(\Large x^2=-28 \implies x= \sqrt{-28}=\sqrt{-1}\sqrt{28} \\ \Large x=2i\sqrt7\)

Answer 16

oh i don't know how i could have missed that. thanks so much,appreciate it!

Answer 17

welcome ^_^