Question

Please help!
1. Find k so that the line through (7, 2k) and (4, -3) is parallel to the line through (1,k+1) and (3,5).

Answer 1

your question is incomplete.

Answer 2

Thanks for catching that- I updated the correct question.

Answer 3

slopes are same.
\[slope=\frac{ y2-y1 }{ x2-x1 }\]
equate the two slopes and find the value of k

Answer 4

This is what I got:
1.) m= -3-2k/4-7=-3-2k/-3=-2k
m=5-k+1/3-1=4-k/2=-k+4/2=-k

What would I do to find the value of k?

Would it be -2k=-1k?

Answer 5

You simplify each slope incorrectly.

Answer 6

Would the correct answer be k=6/7?

Answer 7

\[m_1=\frac{-3-2k}{4-7}=\frac{-3-2k}{-3}\]
\[m_2=\frac{5-(k+1)}{3-1}=\frac{5-k-1}{2}\]

Answer 8

Thank you!!

Answer 9

Well you still to find for what value of k m1=m2.

Answer 10

And yes k=6/7. Good.

Answer 11

So that is the final step?

Answer 12

The last step is to state what k is.