Please help!
1. Find k so that the line through (7, 2k) and (4, -3) is parallel to the line through (1,k+1) and (3,5).

Question

Please help! 
1. Find k so that the line through (7, 2k) and (4, -3) is parallel to the line through (1,k+1) and (3,5).

anonymous · Answer

your question is incomplete.

anonymous · Answer

Thanks for catching that- I updated the correct question.

anonymous · Answer

slopes are same.
$$slope=\frac{ y2-y1 }{ x2-x1 }$$
equate the two slopes and find the value of k

anonymous · Answer

This is what I got:
1.) m= -3-2k/4-7=-3-2k/-3=-2k
m=5-k+1/3-1=4-k/2=-k+4/2=-k

What would I do to find the value of k?

Would it be -2k=-1k?

myininaya · Answer

You simplify each slope incorrectly.

anonymous · Answer

Would the correct answer be k=6/7?

myininaya · Answer

$$m_1=\frac{-3-2k}{4-7}=\frac{-3-2k}{-3}$$
$$m_2=\frac{5-(k+1)}{3-1}=\frac{5-k-1}{2}$$

anonymous · Answer

Thank you!!

myininaya · Answer

Well you still to find for what value of k m1=m2.

myininaya · Answer

And yes k=6/7. Good.

anonymous · Answer

So that is the final step?

myininaya · Answer

The last step is to state what k is.