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Mathematics 23 Online
OpenStudy (anonymous):

find domain: f(x)=x+1/x-2 (can you explain and help me understand how to do this?)

jimthompson5910 (jim_thompson5910):

is the denominator just 'x' or is it 'x-2' ?

OpenStudy (anonymous):

x-2

OpenStudy (anonymous):

The denominator is likely x-2.

jimthompson5910 (jim_thompson5910):

you CANNOT divide by zero if the denominator were zero, then x-2=0 x = 2 so that means if x = 2, then the denominator is zero ------------------------ to avoid division by zero, you have to exclude x = 2 from the domain. Any other number is allowed in the domain so that's why the domain is the set of all real numbers x, but x cannot equal 2

OpenStudy (anonymous):

I dont really get it Can you give me some sort of steps so I know what to do? I have an entire worksheet on this.

jimthompson5910 (jim_thompson5910):

you set the denominator equal to zero, then solve for x this solution you get for x is the value you kick out of the domain (everything else stays in the domain)

jimthompson5910 (jim_thompson5910):

x - 2 = 0 x = 2 therefore the only thing you exclude from the domain is x = 2

jimthompson5910 (jim_thompson5910):

again you're doing this because division by zero is not allowed and it's undefined

OpenStudy (anonymous):

But isnt this about the function, not solving for x?

jimthompson5910 (jim_thompson5910):

yes it is about the function since domains apply to functions (specifically, the input of a function)

jimthompson5910 (jim_thompson5910):

the domain is the set of all allowed inputs of a function ie...the set of allowed x values

jimthompson5910 (jim_thompson5910):

everything is allowed BUT 2 since 2 causes a division by zero error

OpenStudy (anonymous):

i am so confused and frustrated

jimthompson5910 (jim_thompson5910):

let's do another example

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

let's say we have the function f(x) = 1/(x+7) the "x+7" is all in the denominator ---------------------------------- again we cannot divide by zero, so x+7 cannot be zero if it were, then x+7 = 0 turns into x = -7 after we solve for x so x = -7 makes the denominator zero and we have to kick x = -7 out of the domain (to avoid division by zero) so the domain of this function is the set of all real numbers but x cannot equal -7

OpenStudy (anonymous):

im sorry but i am still so confused

jimthompson5910 (jim_thompson5910):

where are you stuck?

OpenStudy (anonymous):

I just cant seem to grasp it. We have done this in class a billion times, but I am not remembering how to do this.

OpenStudy (anonymous):

I am not sure how you got to the answer. Can you put it in some sort of step form?

jimthompson5910 (jim_thompson5910):

I laid out all the steps and the answer. You set the denominator equal to zero, then you solve for x. After getting your solution(s), you know what to kick out of the domain of all real numbers.

OpenStudy (anonymous):

This is the answer I found online: x≠1 (−∞,1) U (1,∞)

jimthompson5910 (jim_thompson5910):

oh so you're not sure how to go from x≠1 to (−∞,1) U (1,∞) btw that's not the answer, but it's close

OpenStudy (anonymous):

Im not sure how to do any part of this problem. I just got that answer from using mathway

jimthompson5910 (jim_thompson5910):

does my explanation make any sense at all?

OpenStudy (anonymous):

no maybe I have a learning disorder

jimthompson5910 (jim_thompson5910):

do you agree that division by zero is not allowed or not defined

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

example: 1/0 is NOT defined

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

so that means we must make sure that the denominator is NOT zero

jimthompson5910 (jim_thompson5910):

IF the denominator were zero, then we'd have problems so that's why we have to set the denominator equal to zero, then solve for x to figure out which value or values of x make the denominator zero making sense?

OpenStudy (anonymous):

but dont we just want the domain of the function

jimthompson5910 (jim_thompson5910):

yes we do, but it turns out that the domain of rational functions hinges on the denominator (because of this division by zero error)

jimthompson5910 (jim_thompson5910):

normally any number would work, BUT because of this division by zero error, we have to check to see which values of x make the denominator zero any we find must be excluded from the domain

OpenStudy (anonymous):

your words are too complicated. I am not as smart as you.

OpenStudy (anonymous):

Thank you for your help, but I do not think I will understand this ever.

jimthompson5910 (jim_thompson5910):

don't give up on it, take a break for a bit, but come back when you feel ready again

OpenStudy (anonymous):

I just dont see how people understand this

jimthompson5910 (jim_thompson5910):

you will soon, trust me

jimthompson5910 (jim_thompson5910):

just try to approach it from a different angle if you have to

OpenStudy (anonymous):

how? No one can help me right now. My dad does not know math. My sister does not know this.

jimthompson5910 (jim_thompson5910):

ok so you agree that something like 1/0 is not allowed, so far so good if we had the expression 1/x, what value of x is NOT allowed?

OpenStudy (anonymous):

Nothing because it is not 0

jimthompson5910 (jim_thompson5910):

so x = 0 is allowed? or no?

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

good, x = 0 is NOT allowed in 1/x since 1/0 is not allowed

jimthompson5910 (jim_thompson5910):

so the domain of 1/x is x≠0 (−∞,0) U (0,∞) those are two fancy ways of saying "everything is allowed but 0"

jimthompson5910 (jim_thompson5910):

does that make sense?

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