Question

a particle is projected from the ground in earth's gravitational field at an angle θ with the horizontal then
A.center of curvature of projectile's trajectory at the highest point is below the ground level if θtan^-1√2 C.center of curvature of projectile's trajectory at the highest point may be above ground level if θ< tan^-1√2

Answer 1

@Abhishek619 pls...help me in dis question

Answer 2

its C

Answer 3

no,the answer is all of these

Answer 4

hahah yeah !

Answer 5

u shud have told that before... i just saw the last option :P

Answer 6

ohkk...bt now i m telling u
Now pls..hlp me how to do dis question

Answer 7

tan^ -1 rt2 =54 degree

Answer 8

ok with it?

Answer 9

yaa sure

Answer 10

no wait how is dis possible we know dat tan(45deg)=1/root 2

Answer 11

that was sin not tan

Answer 12

tan 45 is 1

Answer 13

yaa sorry.....

Answer 14

i was confused a li'l bit in fact a whole of it
my mistake

Answer 15

i got it go ahead....

Answer 16

actually that was not a big issue but i solved ques by my own imagination.. so bringing imagination to words is gonna a bit difficult at dis tym and my body is tending to sleep :P

Answer 17

wat does the term 'center of curvature ' mean ?

Answer 18

focus ?

Answer 19

yes sir... @ganeshie8

Answer 20

ohk then the question is about finding focus of parabola, ok makes some sense now :o

Answer 21

actually that's wht the question demands.....