Question

Differentiate sin(tan(x^2+8x+9)). So would I say u=(x^2+8x+9) Y=sin(tan(u)) I ended up with 1/cos(x^2+8x+9)(2x+8). Is this correct?

Answer 1

no.

Answer 2

i get
cos [tan (x^2 + 8x + 9) 2x + 8 all over cos^2 (x^2 + 8x +9)

Answer 3

sorry, you are correct.

Answer 4

if you use u, it's [cos (tan u)](sec^2 u)(u')

Answer 5

Hmmm. I'm gonna restart this. We literally started this on Friday, so I'm struggling a bit. Thanks, you two!

Answer 6

Okay, good luck!

Answer 7

Just remember to use the chain rule for all those inner and outer derivatives.

Answer 8

Yes! Thanks!