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Derivatives Review: Find the derivative: cos((x^2)+1)+m
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is it sin2x/m'?
Is m a constant or a variable?
i think its a variable
Well then I think the derivative is -2x sin(x^2 + 1) + m'
is that using the chain rule?
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Yup. The outside derivative is the -sin (x^2 + 1) and then multiply by the inner derivative 2x. Then you add the m' (if it turns out that m is not a variable, then you leave this last part out)
thanks!
Welcome!
hi, on wolframalpha it says m is zero
do you mean that there is no m in the final answer? if so, it's probably because m is a constant and not a variable. the derivative of a constant is always zero, so that's why the m goes away.
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