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Mathematics 17 Online
OpenStudy (anonymous):

Derivatives Review: Find the derivative: cos((x^2)+1)+m

OpenStudy (anonymous):

is it sin2x/m'?

OpenStudy (anonymous):

Is m a constant or a variable?

OpenStudy (anonymous):

i think its a variable

OpenStudy (anonymous):

Well then I think the derivative is -2x sin(x^2 + 1) + m'

OpenStudy (anonymous):

is that using the chain rule?

OpenStudy (anonymous):

Yup. The outside derivative is the -sin (x^2 + 1) and then multiply by the inner derivative 2x. Then you add the m' (if it turns out that m is not a variable, then you leave this last part out)

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

Welcome!

OpenStudy (anonymous):

hi, on wolframalpha it says m is zero

OpenStudy (anonymous):

do you mean that there is no m in the final answer? if so, it's probably because m is a constant and not a variable. the derivative of a constant is always zero, so that's why the m goes away.

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