A=P(1+(r/n))^nt isolate r
\(a = P\left( 1 + \dfrac{r}{n} \right) ^{nt} \)
thats correct. i can plug in values if that will help.
No. First, divide both sides by P.
ok done
then what do i do with the exponents?
\(\dfrac{a}{P} = \left( 1 + \dfrac{r}{n} \right) ^{nt}\) Since the right side is raised tot eh nt power, ne we take the nt root of both sides: \( \large \sqrt[nt]{\dfrac{a}{P}} = \sqrt[nt]{\left( 1 + \dfrac{r}{n} \right) ^{nt}}\) \( \large \sqrt[nt]{\dfrac{a}{P}} = 1 + \dfrac{r}{n}\) Now we subtract 1 from both sides: \( \large \sqrt[nt]{\dfrac{a}{P}} -1 = \dfrac{r}{n}\) Now multiply both sides by n: \( \large \large( \sqrt[nt]{\dfrac{a}{P}} -1 \large)n = r\)
in my class we are studying logarithms and exponential functions. if i isolate r will it give me the same answer as if i solve using logarithms?
yes
k cool
thanks
how would i do it using logarithms?
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