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OpenStudy (mathstudent55):
\(a = P\left( 1 + \dfrac{r}{n} \right) ^{nt} \)
OpenStudy (anonymous):
thats correct.
i can plug in values if that will help.
OpenStudy (mathstudent55):
No.
First, divide both sides by P.
OpenStudy (anonymous):
ok done
OpenStudy (anonymous):
then what do i do with the exponents?
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OpenStudy (mathstudent55):
\(\dfrac{a}{P} = \left( 1 + \dfrac{r}{n} \right) ^{nt}\)
Since the right side is raised tot eh nt power, ne we take the nt root of both sides:
\( \large \sqrt[nt]{\dfrac{a}{P}} = \sqrt[nt]{\left( 1 + \dfrac{r}{n} \right) ^{nt}}\)
\( \large \sqrt[nt]{\dfrac{a}{P}} = 1 + \dfrac{r}{n}\)
Now we subtract 1 from both sides:
\( \large \sqrt[nt]{\dfrac{a}{P}} -1 = \dfrac{r}{n}\)
Now multiply both sides by n:
\( \large \large( \sqrt[nt]{\dfrac{a}{P}} -1 \large)n = r\)
OpenStudy (anonymous):
in my class we are studying logarithms and exponential functions. if i isolate r will it give me the same answer as if i solve using logarithms?
OpenStudy (mathstudent55):
yes
OpenStudy (anonymous):
k cool
OpenStudy (anonymous):
thanks
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