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Mathematics 18 Online
OpenStudy (anonymous):

Please Help Exponential Decay See Attachment

OpenStudy (anonymous):

OpenStudy (wolf1728):

Looking at the graph, number of people at year 0 80,000 year 6 40,000 year 12 20,000 So we can say that the "half-life" is 6 years. And the formula for this would be: Present Population = Beginning amount / 2^n (where 'n' is the number of half-lives or (elapsed time/halflife) So what is population after 6 years? Population = 80,000 / 2^(6 yrs / 6yrs) Population = 80,000 / 2^1 Population = 40,000 Now for something a little tougher: Population after 7 years? Population = 80,000 / 2^(7 yrs / 6yrs) Population = 80,000 / 2^(7 yrs / 6yrs) Population = 80,000 / 2^(7/6) Population = 80,000 / 2.2449240966 Population = 35,636

OpenStudy (anonymous):

okay, that makes sense. thank you

OpenStudy (wolf1728):

u r welcome :-)

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