Question

Part A: Solve A = 9/2 (x + 23) for x.

Part B: Determine the value of x when A = 108.

Part C: Solve -np - 90 > 30 for n. Show your work.

Answer 1

@ganeshie8 Help me on this one please??

Answer 2

\(\large A = \frac{9}{2} (x + 23) \)

Answer 3

to solve x, you need to isolate it
you need to get x all by itself

Answer 4

wat shud be ur first step ? :)

Answer 5

I can't do it with fractions :/ I have no clue

Answer 6

me too hate fractions,
so lets get rid of them first

multiply both sides wid 2

Answer 7

\(\large A = \frac{9}{2} (x + 23) \)

multiply both sides wid 2

\(\large 2 \times A = 2 \times \frac{9}{2} (x + 23) \)

Answer 8

\(\large A = \frac{9}{2} (x + 23) \)

multiply both sides wid 2

\(\large 2 \times A = 2 \times \frac{9}{2} (x + 23) \)

\(\large 2A = 9(x + 23) \)

Answer 9

fractions are gone !

Answer 10

Oh thank goodness xD
So then what do i do?

Answer 11

next divide 9 both sides

Answer 12

\(\large A = \frac{9}{2} (x + 23) \)

multiply both sides wid 2

\(\large 2 \times A = 2 \times \frac{9}{2} (x + 23) \)

\(\large 2A = 9(x + 23) \)

divide 9 both sides

\(\large \frac{2A}{9} = x + 23\)

Answer 13

see, \(x\) is looking bit lean now
it has oly 23 attached to it now

get rid of it aswell

Answer 14

wat must we do... to rip off 23 from x

Answer 15

Umm... and then am I supposed to subtract 23 from both sides?

Answer 16

Yes ! you got it !!

Answer 17

\(\large A = \frac{9}{2} (x + 23) \)

multiply both sides wid 2

\(\large 2 \times A = 2 \times \frac{9}{2} (x + 23) \)

\(\large 2A = 9(x + 23) \)

divide 9 both sides

\(\large \frac{2A}{9} = x + 23\)

subtract 23 both sides

\(\large \frac{2A}{9}-23 = x\)

Answer 18

But then that would be what??? how do you subtract 23 from that fraction part thingy??
Thats so confusing!

Answer 19

you cant subtract, so leave it like that

Answer 20

we're done wid part A

Answer 21

Oh wow... Thats confusing

Answer 22

:) get use to it

Answer 23

you wil see lot of these,
u wil become comfortable wid these in no time... dont wry

Answer 24

Okay lol I have no idea what the next question is even asking! >_<

Answer 25

put A = 108 above, and see wat u get

Answer 26

so 2x108?

Answer 27

\(\large \frac{2A}{9}-23 = x\)


put \(A = 108\)
and find \(x\)

Answer 28

Yes !

\(\large \frac{2A}{9}-23 = x\)

put \(A = 108\)

\(\large \frac{2\times 108}{9}-23 = x\)

Answer 29

okay so 216/9-23=x?

Answer 30

Yes

Answer 31

keep going

Answer 32

24-23=x? so 1=x?

Answer 33

perfect !

1 = x

is same as

x = 1

Answer 34

so the value of x when A = 108, is 1

Answer 35

can u do part C ?

Answer 36

Okay thank you :) How about the last one?

Answer 37

you need to rip off things from n and isolate it

Answer 38

No... How do you solve those?

Answer 39

Okay...

Answer 40

give it a try... il help if u get stuck

Answer 41

-np - 90 > 30

Answer 42

okay give me a sec

Answer 43

so -np>120?

Answer 44

-90 is there on \(n\) side,
so get rid of it first by 'adding 90 both sides'

Answer 45

thats right !
keep going

Answer 46

I dunno what to do from there...

Answer 47

add n to both sides>

Answer 48

No.
you want \(n\)

Answer 49

so add p?

Answer 50

since \(p\) is attached to \(n\),
get rid of \(p\) 'by dividing \(p\) both sides'

Answer 51

-np>120

divide p both sides


-n > 120/p

Answer 52

is that my answer?

Answer 53

still n is not all by itself

Answer 54

you need to multiply -1 both sides
to get rid of - sign

Answer 55

-n > 120/p

n < -120/p

Answer 56

How do I do that?

Answer 57

when u multiply NEGATIVE numbers, u need to flip signs

Answer 58

oh so its just n<-120/p

Answer 59

yup

Answer 60

Okay... Thank you!

Answer 61

yw !