Question

could someone expand this expression? y= 5x-2.. substitute in the equation 2x^2 + y^2 - 4x - 14y + 48..

Answer 1

\[2x^2+(5x-2)^2-4x-14(5x-2)+48\]

Answer 2

\[2x^2+(25x^2-20x+4)-4x-70x+28+48\]

Answer 3

\[27x^2-94x+80\]

Answer 4

@silverxx do u get it

Answer 5

its 2 and 40/27

Answer 6

wait.. you have any idea about tangent lines??

Answer 7

yup ...

Answer 8

oh please help./.

Answer 9

sure......i will try,,

Answer 10

2x^2 + y^2 - 4x - 14y + 48 = 0 is perpendicular tp 5x - 2y + 4 = 0

Answer 11

what i did first was getting the dy/dx of the first equation then that serves as the m.

Answer 12

then the second equation convert to the expression y= mx + b

Answer 13

then equate both slope :)

Answer 14

what do u want to do in the que??

Answer 15

and then im lost

Answer 16

derive to tese answers 2x = 5y - 28 = 0 and 15x - 6y + 22 = 0

Answer 17

and 2x + 5y - 46 = 0 and 15x - 6y + 32 = 0

Answer 18

can you pls tell me the whole que....i m little bit confused

Answer 19

find the equations of the tangents and normals.. 2x^2 + y^2 - 4x - 14y + 48 = 0 is perpendicular to 5x - 2y + 4 = 0

Answer 20

given eq is of a circle or what??

Answer 21

it wasnt mentioned..

Answer 22

curve i think

Answer 23

ok...

Answer 24

sorry i m not getting the ans,,

Answer 25

its okay but wait hehe

Answer 26

how can i square y = 5x+2?

Answer 27

y^2=(5x+2)^2
y^2=25x^2+20x+4)

Answer 28

by squaring both the side.

Answer 29

the dy/dx of 2x^2 + y^2 - 4x - 14y + 48?

Answer 30

what do u get?

Answer 31

- 4x + 4/ 2y- 14

Answer 32

yup i also get this..

Answer 33

can you equate that to 2/5?

Answer 34

just to make sure i have same answer with yours