Question

integral ((e^2x)-2)/((e^2x)+3)

Answer 1

Use substitution.

Answer 2

Let u = (e^(2x) + 3)
du = 2 (e^(2x) + 3)

So this integral is of the form 1/2 du/u

So the result is (1/2) ln ((e^2x) + 3)) + C

Answer 3

du = 2 (e^(2x) + 3) or only du=2e^2x

Answer 4

3 is constant, so derivative =0
so its just
du = 2e^2x :)

Answer 5

ok i need the final answer

Answer 6

did you try ?
what did u get ?

Answer 7

\[\frac{ 1 }{ 2 }\ln (e^{2x}+3)-\ln (e^{2x}+3)\]

Answer 8

nopes, that doesn't seem correct....

Answer 9

yes i thought that too

Answer 10

you split it as e^2x/ (....) - 2/ (....) right ?

Answer 11

yes

Answer 12

so the first part is easy, just 1/2 ln (e^2x+3)
you will need partial fractions for 2nd part...

Answer 13

show me how to do
this step (partial fractions)