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Geometry 17 Online
OpenStudy (anonymous):

1. Graph a triangle STU and reflect it over the y axis to create triangle S'T'U part 1 describe the transformation using words part 2 draw a line segment from point s to the reflecting line. what do you notice about the line segments you drew? part 3 do you think you would see the same characteristic if you drew the line segment connecting T with the reflecting line and then T' with the reflecting line? how do you know??

OpenStudy (anonymous):

ive been stuck on this for a few hours today I cant get it

OpenStudy (anonymous):

please someone help me with this?

OpenStudy (anonymous):

Alright do you have graph paper?

OpenStudy (anonymous):

not at hand I have it on my I pod though

OpenStudy (anonymous):

If not, draw a "x" and "y" axis graph with grids on it ranging from 1-5 and -1 to -5 on each side

OpenStudy (anonymous):

Don't use electronics on this one. It's better to understand this conceptually by hand it will help you in the long run,

OpenStudy (anonymous):

okay I drew it out now what? and thank you

OpenStudy (anonymous):

Did you mark 1-5 on the positive and -1 to -5 on the positive and negative sides of the "x" and "y" axis? They should be similar in increments

OpenStudy (anonymous):

yeah I did

OpenStudy (anonymous):

Okay. Now pick points such as (1,2), (1,1) and (3,1) then draw lines connecting them to form your "triangle"

OpenStudy (anonymous):

|dw:1382380617386:dw| should look something similar to that

OpenStudy (anonymous):

Tell me when you're done.

OpenStudy (anonymous):

okay i did it

OpenStudy (anonymous):

Alright name the points "S", "T" and "U". You can pick any points to give them their specific name. After that, we need to reflect it across the "y-axis" as stated by the question, so what you do is turn every "x" value point in your coordinate values to negatives. After you have done that, you should have three coordinates that are similar to your first but have negative "x" values and the same "y" values. You then graph these new coordinates. It should reflect the triangle across your "y-axis" then name these points S' T' and U' so which ever had the "S" before, name the reflected coordinate S'

OpenStudy (anonymous):

okay I got all of that do far

OpenStudy (anonymous):

im mainly just having trouble trying to get the answer and what I ne ed to write down

OpenStudy (anonymous):

The drawing is exactly what we need to help answer your problem. Sometimes it's better to see something visually to understand it. Since you're done, we go to your questions. In your own words describe how the graph was changed, this should be easy to explain as you just did it yourself. So what would you say?

OpenStudy (anonymous):

well we reflected the triangle across the y axis and we turned every x vaule into negatives then we graphed our new coordinates then we named the points S' T U'

OpenStudy (anonymous):

Okay. that's decent enough. Second question, draw your line segments that connects the original "S" and the new S' then tell me what you see

OpenStudy (anonymous):

okay this is where I got confused I didn't understand this parrt

OpenStudy (anonymous):

What don't you understand about it? You are told to draw a line that connects the original "S" coordinate with the reflected S' coordinate. What can you say about the line that you just drew?

OpenStudy (anonymous):

the line helped with the reflection?

OpenStudy (anonymous):

How did it help?

OpenStudy (anonymous):

When images/pictures are reflected across the "y-axis" only they "x" values are changing, in which the "y" values stay the same creating a horizontal line. If were to do the same thing to the "T" to T' and "U" to U' we will see the same response as only their "x" values are changing. In the end you get three horizontal lines.

OpenStudy (anonymous):

yeah and so the line helps in that same exact way right? im sorry im just really out of it

OpenStudy (anonymous):

Yeah, you can add that in to your response. The last question should be easy to answer. Then you are done.

OpenStudy (anonymous):

okay thank you for everything

OpenStudy (anonymous):

You're welcome =)

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