Question

4g is the same as

Answer 1

in what unit do you need it ?

Answer 2

Well, it depends, if by "g" you are referring to the acceleration due to gravity, then you are talking about \(\vec{g}\) and then:
\[4\vec{g}=4(9.8m/s^2[down])=(4\times9.8)m/s^2[down]=39.2m/s^2[down]\]