Question

(sinx-cosx)^(2)- (sinx+cosx)^(2) PLEASE HELP!

Answer 1

http://openstudy.com/study#/updates/525ecf8be4b002bdb091dd99

Answer 2

has some tips and formulas in it.

Answer 3

(sin x - cos x)^2 = sin^2(x) - 2 sinx cosx + cos^2(x)
(sin x + cos x)^2 = sin^2 (x) + 2sinx cox + cos^2(x)

so the first expression minues the second expression is just:
- 4sinx cos x

Answer 4

You could have also done this problem by realizing that sin^2x + cos^2x = 1
so the first expression is just 1-2sin x cos x

And the same for the second expression, you get 1+2sinx cos x


Now subtract, and you'll still get -4 sin x cos x

Answer 5

Your welcome.

Answer 6

alternative :
use the difference square formula :
m^2 - n^2 = (m+n)(m-n)

now, (sinx-cosx)^(2)- (sinx+cosx)^(2)
= (sinx-cosx+sinx+cosx)(sinx-cosx-(sinx+cosx))
= 2sinx(-2cosx)
=-4sinxcos

Answer 7

-4sinxcosx

Answer 8

THANK YOU ALL SO MUCH SERIOUSLY LIFESAVERS....