Question

Help Please??????

Answer 1

ASK!

Answer 2

\[x^{2} + 8x=1\]

Answer 3

What methods to solve this type of equations do you know?

Answer 4

Do you know how to complete the square?

Answer 5

i know im suppose to find 3rd term. but i dont know if its suppose to be something squared to 4?
i know what to do after finding the 3rd term but i dont know how to find it?

Answer 6

Ok, so in this equation, you know that 4+4 would make that 8, you would also have to add 16 to both sides.
So \[x^2+8x+16=1+16\]

Answer 7

B/c with +16 on the left side, the left side is going to be a perfect square.

Answer 8

@Miallions, with me so far?

Answer 9

ok i get it.

Answer 10

so then would the next step be \[(x+4)^{2}=17\] ?

Answer 11

\[x^2+8x+16=17\]
\[(x+4)^2=17\]
\[(x+4)=+-\sqrt{17}\]
\[x= -4-\sqrt{17}\]
or \[x=-4+\sqrt{17}\]

Answer 12

The next step, is to take a square root of both sides

Answer 13

@Miallions, see how I did?

Answer 14

yes i understand now. thanks so much!!!

Answer 15

Anytime! Need more help, tag!

Answer 16

@SolomonZelman i am in need of your assistance.?