Help Please??????

Question

Help Please??????

solomonzelman · Answer

ASK!

anonymous · Answer

$$x^{2} + 8x=1$$

solomonzelman · Answer

What methods to solve this type of equations do you know?

solomonzelman · Answer

Do you know how to complete the square?

anonymous · Answer

i know im suppose to find 3rd term. but i dont know if its suppose to be something squared to 4? 
i know what to do after finding the 3rd term but i dont know how to find it?

solomonzelman · Answer

Ok, so in this equation, you know that 4+4 would make that 8, you would also have to add 16 to both sides.
So $$x^2+8x+16=1+16$$

solomonzelman · Answer

B/c with +16 on the left side, the left side is going to be a perfect square.

solomonzelman · Answer

@Miallions, with me so far?

anonymous · Answer

ok i get it.

anonymous · Answer

so then would the next step be $$(x+4)^{2}=17$$ ?

solomonzelman · Answer

$$x^2+8x+16=17$$
$$(x+4)^2=17$$
$$(x+4)=+-\sqrt{17}$$
$$x= -4-\sqrt{17}$$
or  $$x=-4+\sqrt{17}$$

solomonzelman · Answer

The next step, is to take a square root of both sides

solomonzelman · Answer

@Miallions, see how I did?

anonymous · Answer

yes i understand now. thanks so much!!!

solomonzelman · Answer

Anytime! Need more help, tag!

anonymous · Answer

@SolomonZelman i am in need of your assistance.?