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Determine all solutions of the differential equation y' = -9 y. Use the variables C and x as appropriate.
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If y ' = -9y then to find y, you want the integral of -9y which is -9y^2/2 + C
Express the logarithm equation in exponential form. ln(x + 1) = 2
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\[\Large \frac{dy}{dx}=-9y\qquad\to\qquad \frac{dy}{y}=-9dx\]Integrating:\[\Large \ln y=-9x+c\]Exponentiating:\[\Large y=e^{-9x+c}\qquad\to\qquad y=e^{-9x}\cdot e^c\]Simplifying:\[\Large y=Ce^{-9x}\]
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