Question

Find the derivative.

y= 2t^5 - 9sqrt(t) + 7/t

I'm completely lost. Do you use different derivative rules for different parts of the equation?

Answer 1

\[\Large y\quad=\quad 2t^5-9\sqrt t+\frac{7}{t}\]Let's get it into a more manageable form.\[\Large y\quad=\quad 2t^5-9t^{1/2}+7t^{-1}\]Any confusion on how I rewrote the second and third term?
From here we can simply apply the `Power Rule for Derivatives` to each term!

Answer 2

No, I see what you did.
-9sqrt(t) turns to -9t^1/2 because it's a sqrt.
7/t turns to 7t^-1 because it's a fraction.

Answer 3

k cool :)
We can apply the same rule to all of the terms in this case, which is convenient!

Answer 4

Be careful with your subtraction on the negative exponent.
Recall that if you subtract something from a negative number, it actually gets larger in the negative direction.

Answer 5

I'm still pretty confused...
Okay so, using the Power Rule:

10t^6 - 4.5t^-1/2 -7t^-2

which was wrong, so I suppose I don't understand the concept ^^;

Answer 6

On the first term, Hmmmmmmm check that one again :)

Answer 7

Oh, is it 10t^4?

Answer 8

Yah that looks better!

Answer 9

I think those negative numbers "increasing" kinda messed with your head for a sec there lol

Answer 10

Haha, yeah, looks like it.
That helped a lot, thanks a bunch!

Answer 11

np c: