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f'(x) for f(x)=ln[x^6(x+4)^8(x^2+7)^7]
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I'm not a 1000% on this but If I understand the equation correctly you would get lnx^6 + ln (x+4)^8 + ln (x^2+7)^7 which would then be 6lnx + 8ln x+4 + 7ln x^2+7
i'm sorry, no I think the last line I wrote of simplification is wrong, I believe you would then put into exponential form and solve for x.
like I said, I'm not a hundred percent but im fairly confident it's something similar to that method.
hope this helps
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