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Calculus1
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integration of dx/xlnx
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try to put u = ln x then du= ... ?
i split it to \[\frac{ 1 }{ x } . \frac{ dx }{ lnx }\] and thenlet u= lnx and du=1/x then it would be \[\int\limits_{}^{}du.\frac{ 1 }{ u}\] which = ln(u) which =ln(ln(x)) am i correct?
absolutely correct! :) just don't forget the +c ln (ln x) +c :)
thanks hartnn!
welcome ^_^
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you can also verify it by differentiating the function d/dx (ln (ln x)) = (1/ln x) d/dx (ln x) = 1/ (x ln x)
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