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How do you find the derivative of X^2/X^2+4? I don't understand what you have to do to find the derivative.
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\[x ^{2}/x ^{2}+4\]
Since it is a quotient you use the quotient rule.
\[(\frac{u(x)}{v(x)})'=\frac{u'(x) \cdot v(x) - v'(x) \cdot u(x) }{u^2(x)}\]
\[h(x)=\frac{u(x)}{v(x)}=\frac{x^2}{x^2+4} => u(x)=x^2 \text{ and } v(x)=x^2+4\]
So what is u'(x) and v'(x) equal to?
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0?
Neither u or v are constant functions so no the derivative is not 0.
\[\text{ power rule -> } (x^n)'=nx^{n-1} \] \[\text{ constant rule -> Let c be a constant } (c)'=0\]
\[\text{ if } u(x)=x^2 \text{ then } u'(x)=(x^2)'=? \] \[if v(x)=x^2+1 \text{ then } v'(x)=(x^2+1)'=?\] Write in what the question mark should be for each statement.
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