Question

Divide the polynomial: (2x^4-13x^316x-9x+20)/(x-5)

Answer 1

can you fix you question you maid a mistake

Answer 2

^316

Answer 3

Oh, sorry. =C Yeah, give me a second.

Answer 4

(2x^4-13x^3+16x^2-9x+20)/(x-5)

Answer 5

I'm just wondering... Can I solve this by setting it up for long division, or is there something else I need to do beforehand?

Answer 6

not sure sorry

Answer 7

haven't solved something like this in a long time

Answer 8

haha, okay. Thanks anyways.

Answer 9

@campbell_st .... are you replying?

Answer 10

its just like long division



you are looking to eliminate the leading term

so multiplying (x -5) by 2x^3 will allow you to eliminate 2x^4

there was a remainder of -3x^3, bring down the 16x^2

now multiply (x -5) by -3x^2 and you can eliminate -3x^3

the remainder was x^2, bring down the -9x

so multiply (x -5) by x will allow for the removal of x^2

the remainder was -4x bring down the 20

multiply (x -5) by 4 and you find that there is now no remainder. which means

(x -5) is a factor of the polynomial.

or

\[(x -5)(2x^3 -3x^2 + x -4) = 2x^4 -13x^3 + 16x^2 - 9x + 20\]

hope this helps