Question

Factorise (2u-7v)^2+7v-2u

Answer 1

\[\Large\bf (2u-7v)^2\color{#CC0033}{+7v-2u}\]Let's factor a -1 out of each term in red here:\[\Large\bf (2u-7v)^2\color{#CC0033}{-(-7v+2u)}\]Which we can write like this:\[\Large \bf(2u-7v)^2-(2u-7v)\]From this point, notice that the first and second term have a factor in common, (2u-7v).
I'm going to add some brackets, maybe it will be easier to see where I'm moving things,\[\Large\bf \left[\color{royalblue}{(2u-7v)}^2-\color{royalblue}{(2u-7v)}\right]\]We can factor this common value out of each term, giving us,\[\Large\bf \color{royalblue}{(2u-7v)}\left[(2u-7v)-1\right]\]

Answer 2

Oh also,

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