Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two column proof of the theorem is shown, but the statement and reasons are not in correct order.
@primeralph @koymoi @Easyaspi314@e.cociuba @ehuman
@Easyaspi314
AB = BC becuase of SAS (BD = BD by identity)
AD = DC because it is marked in the diagram, although I wonder why it is not mentioned in the "Given".
So. A. ok thanks!! and then for the previous question i put, is the answer A? thats what i got. thanks !
It is not A (for the first problem). Because A starts off with DE = 1/2 of AC, but thats what we want to prove. So we are not going to start off with a statement that we want to prove.
Oh, ok so do we start of with The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) By the midpoint formula. Which makes the answer B
Look at B
Exactly, B is the logical sequence of arguments...we first build up to show that DE is 1/2 of AC...then we build up to finally show that they are parallel.
Ok cool, i have two more questions i need help with if you have any more time, really appreciate it!
For this one i was thinking B
You can post it..but am flooded with many requests.
Yah, im sure you know your stuff!
I'm sure many others will jump in. Post the question.
I posted it, its a few comments back
And i find that many people avoid long geometry questions. @Easyaspi314 your really the only one who answers them
The problem with Abdul (posted above)...the two triangles are similar because of AA, angle-angle similarity. If you want me to explain this in greater detail, just ask.
Makes sense?
I think i got it. thanks!! then here is the last question if you have the time
By SSS...the sides are congruent in both triangles. Although I do not like this question at all. It's poorly worded and distracting for the student.
Yah, it was confusing. Thanks so much!! You really helped me.
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