Question

about circular motion
We have F = ma. and a = mv^2/r and v = 2pi r/T
what is the function of F respect to T? 1/T?
@agent0smith

Answer 1

Just plug in 2pir/T in place of v.

It'll be F proportional to 1/T since the T is in the denominator.

Answer 2

let me show you the question on my paper. I have to write lab report, I can write out F as you say but for 1/T^2 only.

Answer 3

question3

Answer 4

they ask for 3 separate function of F respect to T, 1/T and 1/T^2

Answer 5

F to 1/T^2, forgot that it's v^2 in the equation

Answer 6

:(

Answer 7

The three functions are just from your given data... the actual relationship will be F to 1/T^2

Answer 8

ha!! don't you see the question? they said :(3separate plots)

Answer 9

Yeah, i saw... you just have to make three graphs. To help you see that it's F to 1/T^2

Answer 10

I don't have F respect to T :(

Answer 11

I got F=(4m^2pi^2r)/T^2 for F with respect to T

Answer 12

is it not respect to 1/T^2??

Answer 13

It's proportional to 1/T^2.

Answer 14

you mean T^-2?

Answer 15

well that's the same thing, so yes

Answer 16

If you plot F vs 1/T^2, it'll make a straight line.

Answer 17

ok, thank you. Let me try but still not sure how to derive to 3 separate Fs

Answer 18

You aren't deriving separate anythings

You should have values for T. Make a list of values of 1/T. Then another with 1/T^2. Then plot each graph of F vs them, one at a time.

Answer 19

oh, got you.... aha. it makes more sense to me. You mean just F vs T , F vs 1/T and F vs 1/T^2, right? right?

Answer 20

Yep. x would be the T, then 1/T, then 1/T^2

Answer 21

Yeah i don't know if they even asked you to derive it.

Answer 22

thanks a ton lalalalala....