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The atomic weight of a newly discovered element is 110.352 amu. It has two naturally occuring isotopes. One has a mass of 111.624 amu. The other has an isotopic mass of 109.875 amu. What is the percent abundance of the last isotope (109.875 amu)?
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Is that all the information you have?
The last isotope will have a higher % abundance because is closer to 110
It's a multiple choice question if that helps: 1. 62.5% 2. 45.8% 3. 27.3% 4. 72.7% 5. 37.5% 6. 54.2%
that does help
it's 72.7
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Trial and error 111.624 f + 109.875 (1 - f) = 110.352. Solving, f = 0.2727, so 1 - f = 0.7273, or 72.73% of the 109.875 amu isotope.
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