Question

pls what is the limit as x turns to 0 of tan3x/sin8x

Answer 1

Use L'hospitals rule.

Answer 2

is it 3/64

Answer 3

I don't know.
Using L'hospitals rule, we have:
\[\lim_{x \rightarrow 0}\frac{ \tan(3x) }{ \sin(8x) } = \lim_{x \rightarrow 0}\frac{ 3\sec^2(3x) }{ 8\cos(8x) }\]
Can you find a value for the second expression?

Answer 4

its true the answer is 3/8 by leting x=0