Question

what is the derivative of sin^2x

Answer 1

Do you know how to apply the power rule? :)

Answer 2

It's like
\[\frac{ d }{ dx } \sin^n (x) = nsin ^{n-1}x (dx)\]

Answer 3

@josh7
its=2sinx

Answer 4

\[(\sin ^{2}x)^{'} =\] 2sinxcosx

Answer 5

u=sinx
(sin^2x)'=f(u)'u'