HELp offering medals. if question is correct. Simplify the radical expression.
answer choices are: and d is not the correct answer so...
a
b
c
im not going to give you d because its wrong.
Look : Just do this work : we have : 16q under Radical * 14q un R \[\sqrt{16q}*\sqrt{14q}=\sqrt{16*14}
you leave the 2 alone, so we will have. \(2\sqrt{\underline{numbers}}\) Now what is \(14q\times4q\)?
\[\sqrt{16q}*\sqrt{14q}= ?\]
have : \[\sqrt{56q^2}=q \sqrt{56}=\sqrt2q{14}\]=d
so whats the answer c?
What is \(14q\times4q\)? That will be under the square root, and that is multiplied by 2.
Yea !!! yea !
@Kenziehulse :Your answer is right !:)
It will give, \(2\sqrt{56q^2}\) which can be rewritten as \(2\times\sqrt{56}\times\sqrt{q^2}\) \(\sqrt{56}=2\sqrt{14}\) \(\sqrt{q^2}=q\) So now we have, \(2\times2\sqrt{14}\times q=~?\)
k im closin gbut im opening another still offering medals for every one of my questions .:)
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