HELp offering medals. if question is correct.
Simplify the radical expression.
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OpenStudy (anonymous):
OpenStudy (anonymous):
answer choices are: and d is not the correct answer so...
OpenStudy (anonymous):
a
OpenStudy (anonymous):
b
OpenStudy (anonymous):
c
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OpenStudy (anonymous):
im not going to give you d because its wrong.
OpenStudy (anonymous):
Look :
Just do this work :
we have :
16q under Radical * 14q un R
\[\sqrt{16q}*\sqrt{14q}=\sqrt{16*14}
OpenStudy (austinl):
you leave the 2 alone, so we will have.
\(2\sqrt{\underline{numbers}}\)
Now what is \(14q\times4q\)?
OpenStudy (anonymous):
\[\sqrt{16q}*\sqrt{14q}= ?\]
OpenStudy (anonymous):
have :
\[\sqrt{56q^2}=q \sqrt{56}=\sqrt2q{14}\]=d
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OpenStudy (anonymous):
so whats the answer c?
OpenStudy (austinl):
What is \(14q\times4q\)?
That will be under the square root, and that is multiplied by 2.
OpenStudy (anonymous):
Yea !!!
yea !
OpenStudy (anonymous):
@Kenziehulse :Your answer is right !:)
OpenStudy (austinl):
It will give,
\(2\sqrt{56q^2}\)
which can be rewritten as
\(2\times\sqrt{56}\times\sqrt{q^2}\)
\(\sqrt{56}=2\sqrt{14}\)
\(\sqrt{q^2}=q\)
So now we have,
\(2\times2\sqrt{14}\times q=~?\)
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OpenStudy (anonymous):
k im closin gbut im opening another still offering medals for every one of my questions .:)