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Mathematics 17 Online
OpenStudy (anonymous):

Simplify the expression. Giving medals.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

OpenStudy (anonymous):

What is the expression?

OpenStudy (anonymous):

i just posted it. choice A is wrong so im not giving that option.

OpenStudy (austinl):

You need to distribute.

OpenStudy (austinl):

\(a(b+c)=ab+ac\)

OpenStudy (anonymous):

b

OpenStudy (anonymous):

do the square root of 6 then the square root of 33 and distribute and solve

OpenStudy (anonymous):

c

OpenStudy (anonymous):

d

OpenStudy (austinl):

@INeeDhElp1. that doesn't work. they aren't square roots.

OpenStudy (anonymous):

what doesnt work?

OpenStudy (austinl):

You can't just take the square root right away.

OpenStudy (anonymous):

then idk how to do it lol

OpenStudy (anonymous):

so whats the answer? i posted the choices.

OpenStudy (anonymous):

Whats the answer?

OpenStudy (austinl):

Do what I posted above, distribute.

OpenStudy (anonymous):

dont know how.

OpenStudy (anonymous):

would it be c?

OpenStudy (anonymous):

would it be c?

OpenStudy (anonymous):

yep its c i finished and got the answer right.

OpenStudy (happinessbreaksbones):

lol austin

OpenStudy (tester97):

hehe

OpenStudy (austinl):

Ok, now that you have gotten the answer, I will give the solution. We have, \(\sqrt{6}(\sqrt{33}+7)\) You need to distribute it out, \(\sqrt{6}\times\sqrt{33} + \sqrt{6}\times7\) Which is, \(\sqrt{198}+7\sqrt{6}\) This simplifies down to, \(3\sqrt{22}+7\sqrt{6}\) Make sense?

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