Question

dy/dx [x^2+y^2=1]

Answer 1

2x + 2y dy/dx = 0 (implicit differentiation on both sides)

2y dy/dx = - 2x

dy/dx = -2x/2y

or dy/dx = -x/y

Done.

Answer 2

thanks

Answer 3

welcome.

Answer 4

By the way, x^2 + y^2 = 1 is a unit circle,

so what the answer is telling us, is that dy.dx, the slope of the tangent line to the circle at ANY point on the circle will have a value of -x/y (where x and y are the coordinates of the point on the circle).