Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given objective function. Objective function: C=6x-4y

OpenStudy (anonymous):

OpenStudy (anonymous):

@piglet9 please help:(

OpenStudy (anonymous):

@jim_thompson5910 please help:(

jimthompson5910 (jim_thompson5910):

are you able to graph this system of inequalities?

OpenStudy (anonymous):

No

jimthompson5910 (jim_thompson5910):

ok let's focus on doing that first to do that, you graph each inequality one at a time

jimthompson5910 (jim_thompson5910):

to graph \(\large x \ge 0\), you graph the line x = 0, then you shade to the right of this line to graph \(\large y \ge 0\), you graph the line y = 0, then you shade above this line to graph \(\large y \le \frac{1}{3}x+3\), you graph the line y = 1/3x+3, then you shade below this line

OpenStudy (anonymous):

it won't let me make graphs though. :/

jimthompson5910 (jim_thompson5910):

do you have graphing paper?

OpenStudy (anonymous):

no. ._.

jimthompson5910 (jim_thompson5910):

ok do you have geogebra?

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

you're supposed to show step by step ow to do the problem.

OpenStudy (anonymous):

on how*

OpenStudy (anonymous):

@ranga can you help?

OpenStudy (ranga):

You have to graph each of the four constraints somewhere using online resources or on a graph paper. They are just 4 lines two of which are just the x & y axes. So you really need to draw just two lines. I don't have any other suggestions other than those already made by @jim_thompson5910

OpenStudy (ranga):

Or perhaps you can find where the last two lines cross the x or y axes manually by solving the equations.

jimthompson5910 (jim_thompson5910):

sorry I got distracted, but I recommend you downloading geogebra it's a graphing calculator that allows you to graph inequalities and you can use them to set up a feasible region

OpenStudy (agent0smith):

|dw:1382665377246:dw| the x>0 and y>0 basically mean we only want this quarter of the graph. The y<1/3x + 3 is graphed using the y-intercept of 3, and a slope of 1/3. the 5>y+x i first subtracted x on both sides, to get y< 5 - x, then use the y-intercept of 5 (couldn't fit it on graph) and slope of -1. The shading shows the region.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!