1. Complete the square.
t^2 - 12 + (What)

3. x^2− 10x − 21 = 0

5. Use the discriminant to determine whether the equation has two distinct real solutions, a single real solution, or no real solutions.
-3x + 2x - 2 = 0

(I did the rest of them thats why it skips some numbers)

Question

1. Complete the square.
t^2 - 12 + (What)

3. x^2− 10x − 21 = 0

5. Use the discriminant to determine whether the equation has two distinct real solutions, a single real solution, or no real solutions.
-3x + 2x - 2 = 0

(I did the rest of them thats why it skips some numbers)

leozap1 · Answer

Will give best response to first to help, and fan all who helps.

anonymous · Answer

what is half of 12?

leozap1 · Answer

6...

shamil98 · Answer

what is half of -12 actually ..

anonymous · Answer

what is $6^2$ ?

leozap1 · Answer

6^2 = 36, half of -12 is -6,

anonymous · Answer

therefore you need to put $36$ for "what" in 
$$t^2 - 12 + (What) $$

leozap1 · Answer

Ok so it would be t^2 - 12 + 36?

anonymous · Answer

yes
it is a perfect square, it is $(t-6)^2$

leozap1 · Answer

Ok thanks what about for #3 & #5 how do I solve those?

anonymous · Answer

$$x^2− 10x − 21 = 0$$ complete the square
start with 
$$x^2-10x=21$$ then make the left hand side a perfect square by adding $25$ as befoer (half of 10 is 5, 5 squared is 25)
and write 
$$(x-5)^2=21+25=46$$

anonymous · Answer

then take the square root of both sides, get 
$$x-5\sqrt{46}$$ or $$x-5=-\sqrt{46}$$

anonymous · Answer

solve for $x$ by adding 5 and get 
$$x=5\pm\sqrt{46}$$

leozap1 · Answer

$$x = \sqrt{46} + 5, 5 - \sqrt{46}$$
So is this the answer?

anonymous · Answer

oh i mean "yes"

leozap1 · Answer

Ok thanks, can you help me with #5 as well please. :)