Prove that if z ∈ C and Re(z^k) ≥ 0 for all k = 1, 2, 3, . . ., then z ∈ [0,∞).
@hartnn Are you able to help?
use the polar form of a complex number
so \(z^k=r^k(cos(k\theta) +isin(k\theta)\) and thus \(Re(z^k)=r^kcos(k\theta) \ge 0 \). but i am not entirely sure what the question is asking, specifically the interval given. What actually needs to be proved?
prove that that \(\theta=0\)
oh ok that makes more sense to me now as the sine term will vanish. How would i go about proving \(\theta = 0 \)
Assume \(\theta\ne0\) and derive a contadiction
you will also have to take care of the times when \(cos(\theta)=0\) ie \(\theta=\pm\dfrac{\pi}{2}\) though those are easy to resolve.
can you help me with the proof, im not sure how to do it
show there is some k such that \(\cos(k\theta)<0\)
i'm stuck i dont know how to start the proof
@phi you able to help?
@thomaster Are you able to help?
@goformit100
Ya say?
are you able to help me with this proof?
Sorry Sir I don't know it's proof
ok no worries
if i give you much more...i might as well do the entire problem
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