The velocity of a particle moving along X axis is given by v=x^3-4x^2+6x where v is in feet per second and x in feet. Compute the value of the acceleration when x=2ft

Question

anonymous · Answer

You  should take derivative of v, then you get the acceleration. After that you should put x=2 ft into the equation.

anonymous · Answer

is v=ds/dt the formula that i should use??
thanks..

anonymous · Answer

$$a=\frac{ dv }{ dt }$$  you should use this.

anonymous · Answer

wow thanks sir.. i get it already.. first i get the derivative of $$v=x^3-4x^2+6x$$ then i subst the x to 2 then thats the answer right?

anonymous · Answer

i got 2ft/sec as my ans..

anonymous · Answer

yes, your result is right except unit.. it should be ft/sec^2

anonymous · Answer

oh yeah sorry forgot the other sec i have another question sir hope you can help me out again

anonymous · Answer

anytime..