Question

Can't remember how to do this? Please just tell me what to do. I don't want an answer.

Answer 1

@ganeshie8

Answer 2

@phi @jdoe0001 Any of you know how to do this?

Answer 3

hmm brb

Answer 4

@jdoe0001 please

Answer 5

ha!! that guy!!

Answer 6

look at ABC , AB = x+ x+5 = 2x+5
BC = x-2+x+1 = 2x-1
got this part?

Answer 7

Yes I get this.

Answer 8

so, to similar triangle's property , you have
\[\frac{BD}{BA}= \frac{BE}{BC}\] just replace the length of the sides and solve for x. 1 equation, 1 variable, it is solvable

Answer 9

Ahh okay thank you. I just couldn't remember!

Answer 10

ok

Answer 11

\[\frac{ x }{ x +x+5 }=\frac{ x-2 }{ x-2+x+1 }\]
Well this make x+5 = x+1?
Or is it
\[\frac{ x }{ 2x + 5 }=\frac{ x - 2 }{ 2x-1 }\]

Answer 12

last one

Answer 13

Okay
So I'm lost on how to solve for x.

Answer 14

the condition is x \(\neq\)1/2 and x\(\neq\) -5/2 to make sure the equation defined