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Physics 22 Online
OpenStudy (anonymous):

An object falls freely from rest near the surface of Earth, What is the speed of the object after having fallen a distance at 4,90 meters...how do i solve this?

OpenStudy (anonymous):

I'd use the kinematic equation: v^2 = v^2 + 2as, where a is gravity s is the distance fallen [given] and the v on the left is the speed of the the object after falling 490meters and the v on the right is the initial speed, which in our case will be zero, because the question says, 'the object falls from free falll'

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