Question

@ganeshie8 Calculus help please?

Answer 1

the intervals are of length \(\frac{\pi}{4}\)
the left hand rectangle of the first picture as base \(\frac{\pi}{4}\) and height \(\sin(\frac{\pi}{4})=\frac{\sqrt2}{2}\) so the area is the product of those two numbers

Answer 2

the next rectangle in the same picture also has base \(\frac{\pi}{4}\) but the height is \(\sin(\frac{\pi}{2})=1\)

Answer 3

the third rectangle has the same base and height as the first rectangle
so the total area is
\[\frac{\pi}{4}\left(\frac{\sqrt2}{2}+1+\frac{\sqrt2}{2}\right)\]

Answer 4

@ganeshie8 please

Answer 5

@satellite73 Is that when y=sin?

Answer 6

No, when y = sin, you should repent and rethink your life.

Answer 7

:(

Answer 8

You are picking the x-values and evaluating the function y = sin(x). The spacing of the x-values provides the width of the individual rectangles and the value of the function, y = sin(x) in this case, provides the height of the individual rectangles.