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The molecular weight of KCI is 75.How much dry reagent (KCI) is needed to make the following solution. 75 ml of a 4M solution
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@Luigi0210
@Mertsj
For a 1M solution you would need 75 g KCl in 1 liter of solution For a 4 M solution you would need 4(75)g KCl in 1 liter of solution That would be 300 g KCL in 1 liter of solution. But you want to know how much you need for 75 ml of solution so write: \[\frac{300g}{1000ml}=\frac{x g}{75 ml}\]
now what?
do i cross multiply
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rob can you help me finish
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