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OpenStudy (anonymous):

The molecular weight of KCI is 75.How much dry reagent (KCI) is needed to make the following solution. 75 ml of a 4M solution

OpenStudy (anonymous):

@Luigi0210

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

For a 1M solution you would need 75 g KCl in 1 liter of solution For a 4 M solution you would need 4(75)g KCl in 1 liter of solution That would be 300 g KCL in 1 liter of solution. But you want to know how much you need for 75 ml of solution so write: \[\frac{300g}{1000ml}=\frac{x g}{75 ml}\]

OpenStudy (anonymous):

now what?

OpenStudy (anonymous):

do i cross multiply

OpenStudy (anonymous):

rob can you help me finish

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