Question

I just want to make sure I'm doing this right:

find dy/dx by implicit differentiation
x^3-xy+y^2=4

Answer 1

\[3x ^{2}-\left(\begin{matrix}dy \\dx\end{matrix}\right)+2y \left(\begin{matrix}dy \\dx\end{matrix}\right)=0\]

Answer 2

right?

Answer 3

For the middle term apply product rule. The last two terms are correct.

Answer 4

x^3-xy+y^2=4
3x^2 - y -x(dy/dx) + 2y(dydx) = 0
dy/dx = (3x^2 - y)/(x - 2y)

Answer 5

Oh! ok thank you!