Question

Help!!

Answer 1

Simplify the expression.

Answer 2

\[
\Large \frac{ \;\;\frac{x^2 + 2x + 1}{x-2} \;\; }
{ \frac{x^2 - 1}{x^2-4} } \normalsize = \frac{(x^2 + 2x + 1)(x^2-4)}{(x-2)(x^2-1)}
\]
Now.. to the different parts:
\[
(x^2 +2x + 1) = (x+1)^2 \\
(x^2 - 4) = (x+2)(x-2) \\
(x^2 - 1) = (x+1)(x-1)
\]
Plugging in:
\[
\frac{(x^2 + 2x + 1)(x^2-4)}{(x-2)(x^2-1)} = \frac{(x+1)^2 \cdot (x+2)(x-2)}{(x-2) \cdot (x+1)(x-1)} =\\
= \frac{(x+1) (x+2)}{(x-1)}
\]

Answer 3

Thanks.